Of course with my 4 years of experience playing waterpolo, i feel that it is only right that i impart some skills to you n00bs here.
First, let us look at the ball. It's round duh. But there are different types of ball. The man size one is probably r=2sin(t) or r=3sin(t). That is if you plot it in polar coodinates. Now as we all know the volume should 2/3 pie r^3 so if you differentiate it you will get 4/3 pie r^2. That is the surface area of the ball duh. This is especially important. Now find the area of your palm which is also the area under the graph. Now what graph you have really depends here. Most have sin graphs while some freaks have tangent graphs which means you cant really find the area. Now integrate it from zero to 5 to find the area of your palm. If you have 4 fingers then integrate it to 4 then. Now compare it to the area of the ball. Does it achieve the ratio of 1:1.618? It does? WELL DONE!
You can now start playing waterpolo! XD
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